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(9-q)^2=1+3q
We move all terms to the left:
(9-q)^2-(1+3q)=0
We add all the numbers together, and all the variables
(-1q+9)^2-(3q+1)=0
We get rid of parentheses
(-1q+9)^2-3q-1=0
We add all the numbers together, and all the variables
-3q+(-1q+9)^2-1=0
We move all terms containing q to the left, all other terms to the right
-3q+(-1q+9)^2=1
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